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py/objstr: Don't treat bytes as unicode in str.count.

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`b'\xaa \xaa'.count(b'\xaa')` now (correctly) returns 2 instead of 1.

Fixes issue #9404.

This work was funded through GitHub Sponsors.

Signed-off-by: Jim Mussared <jim.mussared@gmail.com>
This commit is contained in:
Jim Mussared
2022-09-25 22:15:45 +10:00
committed by Damien George
parent dd9dcb594c
commit 9d6f474ea4
2 changed files with 10 additions and 1 deletions
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7
tests/basics/bytes_count.py
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@@ -48,6 +48,13 @@ print(b"aaaa".count(b'a', 1, 5))
print(b"aaaa".count(b'a', -1, 5))
print(b"abbabba".count(b"abba"))
print(b'\xaa \xaa'.count(b'\xaa'))
print(b'\xaa \xaa \xaa \xaa'.count(b'\xaa'))
print(b'\xaa \xaa \xaa \xaa'.count(b'\xaa'), 1)
print(b'\xaa \xaa \xaa \xaa'.count(b'\xaa'), 2)
print(b'\xaa \xaa \xaa \xaa'.count(b'\xaa'), 1, 3)
print(b'\xaa \xaa \xaa \xaa'.count(b'\xaa'), 2, 3)
def t():
return True